什么是COA全称是什么–
求函数y=2√2sin(x–兀/8)+sin2x–coa2x的最小值 -
sin2x-cos2x=√2(sin2xcosπ/4-cos2xsinπ/4)√2sin(2x-π/4)设x-π/8=u,则原式=√2(2sinu+sin2u)所以最小值是√2x(3√3/2)-3√6/2
sin2x-cos2x=√2(sin2xcosπ/4-cos2xsinπ/4)√2sin(2x-π/4)设x-π/8=u,则原式=√2(2sinu+sin2u)所以最小值是√2x(3√3/2)-3√6/2